Question

if the base of isosceles is 24 cm and it's area is 60 cm then find its perimeter

Answer 1

Base of triangle = 24cm
area of isosceles triangle = b under root 4a²-b²/4
60 = 24 Under root 4a²-(24)²/4
a =5.5cm
Therefore,
perimeter of isosceles triangle = 2a + b = 2(5.5)+24 = 35 cm

Answer 2

Area of iso. Triangle = 1/2 × b × h
60= 1/2 × 24 × h
60/12 = h
5 = h
H^ = P^ + B^ ( Pythagoras theorem)
AB^= 5^+12^
AB^= 25+144
✔ AB=✔169 (✔ = sq. root)
AB =13
AB =AC= 13
Perimeter of isosceles triangle = 13+13+24 = 50 cm