Question

if the base of isosceles triangle exceeds one of the equal sides by 10 cm and perimeter is 70 cm equal side of a triangle is

Answer 1

let the equal sides be x and x
base=x+10
atq
perimeter of triangle=side+side+side
x+x+x+10=70
3x+10=70
3x=60
x=60/3
=20

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Answer 2

Answer:

Step-by-step explanation:

let the base be x+10

let the 2 other sides be x,x

now ,

total perimeter=70cm

ATP,

x+x+(x+10)=70

x+x+x=70-10cm

3x=60cm

x=20

x=20

x+10=30