Question

If the bigger number is 90, in the two numbers having LCM 5600 and HFC 9, find the smaller number

Answer 1

Answer:

Let the HCF be x

LCM=HCF+900

LCM=x+900 --(1)

And

LCM+HCF=1260

LCM+x=1260 --(2)

From (1) and (2)

(x+900)+x=1260

2x+900=1260

2x=1260−900

2x=360

x=

2

360

x=180

HCF =180

And, from (1),

LCM=HCF+900

LCM=180+900

LCM=1080

By formula, product of the numbers is equal to the product of their HCF and LCM.

Product of numbers =HCF×LCM

=180×1080

Product =194400