Physics, asked by sharmagourav7151, 11 months ago

If the binding energy of electron in hydrogen atom is 13.6 electron volt the energy of the first excited state of lithium dipositve is

Answers

Answered by balaji3107
2

Explanation:

n=2(first excited state)

using formula

E= -13.6×z×z÷n2

E= —30.6eV

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