Physics, asked by bottiravi, 11 months ago


If the binding energy of the electron in a hydrogen atom
is 13.6eV, the energy required to remove the electron
from the first excited state of Lit+ is [AIEEE 2003]
(a) 30.6eV (b) 13.6 eV (c) 3.4 eV (d) 122.4eV

Answers

Answered by prasadutkarsh9
3

Answer-

30.6eV

Explanation:

Energy levels for hydrogen like atom

13.6 × Z²

where, Z is atomic number and n is orbital quantum number for Li++, Z= 3 , n = 2 for the first excited state

Hence, energy of first excited state Li++ = -(13.6 × 9) ÷ 4 =-30.6eV

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