If the bisector of an angle of a triangle also bisects the opposite side, prove that the triangle is isosceles.
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Answer:
The proof is explained step-wise below :
Step-by-step explanation:
For better understanding of the solution, see the attached figure :
In ΔABD and ΔEDC
AD = DE ( By construction)
∠1 = ∠2 ( Vertical opposite angles are equal)
BD = CD ( Given )
By SAS congruency criterion , ΔABD ≅ ΔEDC
So, By using the property of congruency , Corresponding parts of congruent triangles are equal
⇒ AB = CE............(1) and ∠BAD = ∠CED
Also, ∠BAD = ∠CAD ( AD is bisector of ∠BAC)
⇒ ∠CED = ∠CAD
⇒ AC = CE .......(2)
From equation (1) and equation (2)
AB = AC
So, ABC is an isosceles triangle.
Hence Proved.
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