Question

If the bisector of an angle of a triangle also bisects the opposite side, prove that the
triangle is isosceles.
​please answer me fast . If I like your answer then I'll mark as a brain list

Answer 1

Answer:

suppose a triangle ABC and bisector of angle A bisects opposite side BC at D

Step-by-step explanation:

now in triangle ADB and ADC

AD =AD (common)

angle DAB = angle DAC (given)

DB=DC (given)

so ADB congruent ADC

AB=AC (byCPCT)

Because its sides are equal

so it's angles are also equal

hence it's a isosceles triangle

Answer 2

Answer:

Pls mark as brailiest if it helps.

Step-by-step explanation:

So, Lets take a triangle ABC. In which < A is being bisected and the opposite line BC is being bisected at point D.

So, We will the pythagoras theorem.

So, we can say that,

(AD)² + ( DC)² = ( AC) ²

And

(AD)² + (DB)² = (AB)²

Now we know that DB and DC are equal because they were being bisected and AD is common. Hence

We can say that Line AB = AC .

Hence it is proved that it is an isosceles traingle..