If the bisector of an angle of a triangle bisects the opposite side, prove that the triangle is isosceles.
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Consider the ∆ABC, let AD be the bisector of ∠A and BD = CD. It is required to prove ∆ABC is an isosceles triangle i.e. AB = AC. For this draw a line from C parallel AD and extend BA. ... ∴ ∆ABC is an isosceles triangle.
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