Question

if the bisector of angle abc and angle acb of triangle abc meet at point o,prove that angle boc= 90+1/2angle a

Answer 1

Answer:

Step-by-step explanation:

☆in triangle ABC , we have

angle [A+ B+C ] = 180° .

=》1 /2 [A+ B+ C ] = 90°

=》 1/2 A + <OBC + <OCB = 90°

=>> <OBC + <OCB = 90 °- 1 /2 angle A ____eq(1)

NOW in trianglel OBC,

<OBC + <OCB + angle BOC  = 180          

90 - 1/2 angleA + angle BOC = 180           FROM 1

angle BOC = 90degree + 1/2 angle A.

Hence,it is proved.

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