if the bisector of angle xyz and angle xzpmeet at point q then prove angle yqz = half angle yxz
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Answer:
The internal bisector of ∠X meets YZ at P
XZ
XY
=
PZ
YP
(Angle bisector theorem)
Add 1 on both the sides
⇒
XZ
XY
+1=
PZ
YP
+1
⇒
XZ
XY+XZ
=
PZ
YP+PZ
=
PZ
YZ
Step-by-step explanation:
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