If the bisector of the angle A is at right angles to the side BC, then evaluate ∠B-∠C.
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Correct option is
A
cos(2B−C)
θ=B+2A
We know that in any triangle, ∠A+∠B+∠C=π
⇒θ=B+2π−(B+C)
=B+2π−2B−2C
=2π+2B−2C
=2π+2B−C
∴sinθ=sin(2π+2B−C)=cos(2B−C
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