If the bisector of the exterior vertical
base,
angle of a triangle is parallel to the base.
show that the triangle is isosceles.
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Answer:
Join A to D
Hence,
AD∥BC
⇒∠ACB=∠CAD(alternateangle)
⇒and∠BAC=∠ACD(alternateangle)
⇒
Hence
AB=AC (by ASA congurency )
so, it is isosceles triangle.
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