If the bisectors of a pair of alternate angles formed by a transversal with two given lines are parallel, prove that the given lines are parallel.
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⏩In order to prove that AB || CD, it is sufficient to show that,
angle AGH = angle DHG
Now, GM is the bisector of angle AGH and HL is the bisector of angle DHG
=> angle 1 = angle 2 and angle 3 = angle 4 [ consider it as equation (1)]
It is given that GM || HL and transversal EF interests them at G and H respectively.
Therefore,
angle 2 = angle 3 [Alternate angles]
=> angle 1 = angle 4 [ Therefore, angle 2 = angle 1 and angle 3 = angle 4, from (1)]
Therefore,
angle 1 + angle 2 = angle 3 + angle 4
=> angle AGH = angle DHG
=> AB || CD [Hence proved]
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Hope it helps...:-)
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