Question

if the bisectors of angle ABC and ACB of a triangle ABC meet at a point O, then prove that <BOC=90° +1/2 <A.

Answer 1

hey frnd ☺☺☺

==================

☆in triangle ABC , we have

angle [A+ B+C ] = 180° .

=》1 /2 [A+ B+ C ] = 90°

=》 1/2 A + angle 1 + angel 2 = 90°

=>> angle 1 + angle 2 = 90 °- 1 /2 angle A ____eq(1)
NOW in trianglel OBC,

angle1 + angle2 + angle BOC  = 180          

90 - 1/2 angleA + angle BOC = 180           FROM 1

angle BOC = 90degree + 1/2 angle A.

Hence,it is proved.
=========÷÷÷=========÷÷÷========÷÷÷===

HOPE IT HELPS⤴⤴⤴

@@@@@@@@@@@@@@@@@@@