Question

If the bisectors of the exterior angles B and C formed by producing sides AB & AC of ∆ ABC intersect each other at the point O. Prove that : BOC = .

Answer 1

Answer:

answer:90°-x°/2

Step-by-step explanation:

according to the theorem, if the sides AB and AC of a ∆ABC are produced to p and Q respectively and the bisectors of <PBC & <QCB intersect. at O, therefore

we get,

<BOC=90°-1/2<A

hence, in ∆ABC

<BOC=90°-1/2A

<BOC=90°-1/2X

thus,

<BOC =90°X/2

hope,it may helpful to you....