Math, asked by nas5, 1 year ago

If the bisectors of two adjacent angles form a right angle then prove that their non common arms are in same straight line

Answers

Answered by pinquancaro
20

Refer to the attached image.

Let \angle ABD and \angle BDC be two adjacent angles.

Let BE be the bisector of angle ABD and BF be the bisector of angle BDC.

And angle EBF = 90 degree (Given)

To prove:  That the non common arms are in same straight line.

That is to prove that the arms AB and BC are in straight line.

Proof:

Since, angle ABD and angle BDC are the adjacent angles.

The adjacent angles forms linear pair, that is the sum of these angles is 180 degrees.

angle ABD + angle BDC = 180 degrees.

Therefore, AB and BC are in straight line.

Hence, the non common arms are in same straight line.

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Answered by jaswant43
3

Let \angle ABD∠ABD and \angle BDC∠BDC be two adjacent angles.

Let BE be the bisector of angle ABD and BF be the bisector of angle BDC.

And angle EBF = 90 degree (Given)

To prove: That the non common arms are in same straight line.

That is to prove that the arms AB and BC are in straight line.

Proof:

Since, angle ABD and angle BDC are the adjacent angles.

The adjacent angles forms linear pair, that is the sum of these angles is 180 degrees.

angle ABD + angle BDC = 180 degrees.

Therefore, AB and BC are in straight line.

Hence, the non common arms are in same straight line.

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