If the blocks are placed on smooth
plane as shown in figure. If they are
released simultaneously on smooth
plane, then find exerted (R) by 20 kg
block on 5 kg block:
0-300
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Answer:
Explanation:
ANSWER
By applying force balance equation on all the three free masses
The acceleration of all the three masses = a
let all the three masses are a system of 7 kg moving in one direction
So, the acceleration of all the masses is same as combined mass,
a=
totalmass
netforce
a=
2+4+1
120−50
=
7
70
=10
Apply force balance equation to all the masses individually
formass1kg
120−N
1
=1X10
120−N
1
=10
N
1
=110N
formass4kg
N
1
−N
2
=4X10
N
1
−N
2
=40
hereN
1
= 110N
then,N
2
= 110−40=70N
for mass 2kg net force in the direction of N
2
then net force on mass 2kg is
F=N
2
−50
F=70−50=20N
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