If the blocks move with the same acceleration then change in the length of spring is:
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Answer:i think the answer is Zero
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Given:
Mass of block 1= 40kg
Mass of block 2= 60kg
Spring constant= 100N/m
To find:
Extension in spring
Solution:
The net force acting on system = 60N-40N=20N
Let a be the acceleration of two boxes and y be the extension in spring
For block 1,
20-100y=40a
For block 2,
100y=60a
Solving the two equations,
60-300y=200y
or y=6/50m = 0.12m
Hence, extension in spring is c) 0.1m.
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