Question

If the body is projected with the speed of 4m/s at the angle of 60 degree. what is the velocity of body at the highest point?

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

The kinetic energy at the highest point 1 would be equal tom (u cos B)² as the

vertical component of the velocity is zero. The initial kinetic energy is the maximum kinetic energy. So, KEK cos²

3

Thus, K cos²ß = K

⇒ cosß =

√3

2

⇒ B=30°.