Question

if the body of mass 55 kg is released from a height of 10m calculate the change the potential energy when it touches the surface​

Answer 1

Explanation:

m = 55 kg

h₁ = 10 m

h₂ = 0 m

g = 10 m/s

When at height,

P.E.₁ = mgh₁ = 55×10×10 = 5500J

When touches the surface,

P.E.₂ = mgh₂ = 55×10×0 = 0J

Difference in P.E. = P.E.₁ - P.E.₂ = 5500J - 0J = 5500J