If the bond energies of H–H, Br – Br and H –Br are 433, 192 and 364kJmol–1 respectively the ΔHo for the reaction H2(g)+Br2(g)→2HBr(g) is-
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2 H-Br bonds are present so 2×364=728kjmol^-1. 1H-H bond so 433 and 1Br-Br bond so 192kjmol^-1. Products -reactants. 728-433-192=103kjmol^-1 is the delta H value.
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