If the bond lengths of C–C; C–H and C–Cl are 1.54 A0, 1.07 A0 and 1.77 A0 respectively, then radii of H, C and Cl atoms are respectively. (1) 0.30 , 0.77 , 1.00 A0 (2) 1.77 , 0.30 , 1.00 A0 (3) 1.00 , 0.30 , 0.77 A0 (4) 1.00 , 1.50 , 1.77 A0
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CHEMISTRY
Atoms of element B from HCP lattice and those of the element A occupy 2/3 rd of tetrahedral voids. What is the formula of the compound formed by the elements A and B?
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Given that, atoms of B forms hcp lattice. So, the atoms at corners are shared by 6 unit cells. So, its contribution is
6
1
; Face centered atoms contribute
2
1
and middle layer atoms contribute 1 each.
So, effective number of atoms in unit cell =
6
1
×12+
2
1
×2+1×3
=2+1+3=6
Number of tetrahedral voids =2× Number of atoms forming the lattice.
=2×6=12
So, number of atoms of A=
3
2
×12=8
Number of atoms of B=6
So, A:B⇒A:B
8:6 4:3
So, formula is A
4
B
3
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