If the Boolean expression (p ⊕ q) ∧ (~pΘq) is equivalent to p ∧ q , where ⊕ , Θ ∈ {∧, ∨}, then the ordered pair (⊕, Θ) is : (A) (∨, ∧) (B) (∨, ∨)
(C) (∧, ∨) (D) (∧, ∧)
[JEE Main 2019]
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then the ordered pair (⊕, Θ) is ( ∧ , ∨ )
Lets check each option.
( A ) ( ∨ , ∧ ) =
- ( p ∨ q ) ∧ ( ~ p ∧ q ) = ( ~p ∧ q )
( B ) ( ∨, ∨ ) =
- ( p ∨ q ) ∧ ( ~p ∨ q ) = ( ( p ∨ q ) ∧ ~p ) ∨ ( ( p ∨ q ) ∧ q )
- = null set ∨ q = q
( C ) ( ∧ , ∨ ) =
- ( p ∧ q ) ∧ ( ~p ∨ q ) = { ( p ∧ q ) ∧ ~p } ∨ { ( p ∧ q ) ∧ q }= null ∨ ( p ∧ q )
- = p ∧ q
( D ) ( ∧ , ∧ ) =
- ( p ∧ q ) ∧ ( ~p ∧ q ) = ( ( p ∧ q ) ∧ ~p ) ∧ ( ( p ∧ q ) ∧ q ) =
- = null set ∧ ( p ∧ q ) = null set
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