Question

if the both (x+1) and (2x+1) are factors of ax^2+2x+b, then find the value of a-b​

Answer 1

Step-by-step explanation:

first case x+1

x=-1

putting the value of x in

ax^2+2x+b we get

a(-1) ^2 +2x-1 +but

a-2+b=0

in second case 2x+1

2x=-1

x=_1/2

putting the value of x in

ax^2+2x+b we get

a(_1/2) ^2+2 (_1/2) +b

_a/4-1+b

taking lcm we get 4 as lcm

so

-a -4 +b=0

______

4

we get

-a -4 +b

solving both the equation simultaneously

a + b=2

-a +b = 4

________

2b=6

b=3

putting value of b in equation

a+b=2

a+3=2

a=2-3

a=-1

Thank You