Question

If the bottom of a ship is 15.8 below the surface of the sea, calculate the pressure at the bottom of the ship. The density of the seawater is 1030kg/m3

Answer 1

Given:

The bottom of a ship is 15.8 below the surface of the sea and the density of the seawater is 1030 kg/m³.

To Find:

Calculate the pressure at the bottom of the ship.

Solution:

Density of sea water is given below:

$\mathbf{Density(\rho ) = 1030 \ \ \ \dfrac{kg}{m^{3}} }$

Depth of sea water is given below:

Depth (H) = 15.8     m

$\mathbf{Gravitational\ acceleration \ (g) = 10 \ \ \ \dfrac{m}{s^{2}} }$

From formula of Hydro-static pressure:

$\mathbf{Pressure\ (P) = \rho \times g\times H \ \ \ \dfrac{N}{m^{2}} }$

On putting respective value:

$\mathbf{Pressure\ (P) = 1030 \times 10\times 15.8 \ \ \ \dfrac{N}{m^{2}} }$

$\mathbf{Pressure\ (P) =162740 \ \ \ \dfrac{N}{m^{2}} }$

Means pressure at bottom of ship is 162740 Pa.