If the breaking stress of a wire is 2×10⁵ N/m² find the minimum cross section area of the wire so that it doesn't break
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Class 11
>>Physics
>>Mechanical Properties of Solids
>>Hooke's Law
>>Breaking stress of a material is 2 × 10
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Breaking stress of a material is 2×10
8
N/m
2
. What maximum length of the wire of this material can be so that the wire does not break my own weight? [Density of material =5×10
3
kg/m
3
]
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Solution
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Correct option is D)
Let length =L
So, mass of length L=( Density of wire) (volume of wire)
Density of wire =ρ=5×10
3
Kg/m
3
Volume =LA(A= Area of cross section )
Stress=
Area
Force
2×10
8
=
A
mg
=
A
ρLAq
So, L=
ρ×g
2×10
8
=
5×10
3
×10
2×10
8
L=4000 m
L=4 km
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