Question

if the bus starting from rest then sum times ofter reproduce of extratiom 10ms in 10 s find the value of distance​

Answer 1

Answer:

A bus starts from rest with an acceleration of 1.0m/s2. A man who is 48m behind the bus, starts with a uniform velocity of 10m/s. Find the minimum time after which the man will catch the bus.

Answer 2

Answer:

Explanation:

Solution :-

Initial speed of bus, u = 0 (As starts from rest)

Acceleration of bus, a = 10 m/s²

Time taken by bus, t = 10 seconds.

To Calculate :-

Distance traveled, s = ??

Formula to be used :-

2nd equation of motion,

i.e, s = ut + 1/2at²

Solution :-

Putting all the values, we get

s = ut + 1/2at²

⇒ s = 0 × 10 + 1/2 × 10 × 10²

⇒ s = 1/2 × 10 × 100

⇒ s = 5 × 100

⇒ s = 500 m.

Hence, the distance traveled is 500 m.