Question

If the capacitance of a parallel plate capacitor is 100meuF and the potential difference is 70meuF, the quantity of charge stored on each plate would be? ​

Answer 1

Answer:

Solution :

(a) Charge = capacitance xx potential diff. <br>

<br> (b) When dielectrical is introduced , potential difference decreases <br>

<br>

(c ) Charge = Capacitnace xx P.d .

q' = q_i - q_f

5 m C - 2 mC = 3mC.

Explanation:

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