Question

If the capacity of a cylindrical tank is 1848m^3 and the diameter of its base is 28 m, find the depth of the tank.​

answer hai 3 m..

Answer 1

Hey friend,

Here is the solution :-

$here \: volume \: of \: the \: cylinder \: is \: given \: as \: 1848 \: {m}^{3} \\ \\ and \: diameter \: of \: the \: base \: as \: 28 \: m \\ \\ radius \: = \frac{diameter}{2} = \frac{28}{2} = 14 \: m \\ \\ volume \: = \pi {r}^{2} h = 1848 \\ \\ therefore \: \: \: \: \frac{22}{7} \times {14}^{2} \times h = 1848 \\ \\ \frac{22}{7} \times 14 \times 14 \times h = 1848 \\ \\ \frac{22 \times 14 \times 14}{7} \times h = 1848 \\ \\ \frac{4312}{7} \times h = 1848 \\ \\ 616 \times h = 1848 \\ \\ h = \frac{1848}{616} = 3$

Here we get the height of the cylinder as 3 meter.

✨I hope this will help you....✨

Answer 2

Trigonometry, the branch of mathematics concerned with specific functions of angles and their application to calculations. There are six functions of an angle commonly used in trigonometry. Their names and abbreviations are sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (csc).