Question

If the car is travelling with the velocity of 3 m/s .If the acceleration of 9.3 m/s^2 is produced for 1.8 seconds , find the distance travelled in this time

Answer 1

ANSWER

Given Final velocity (v) = 50 m/s

Initial velocity (u) = 30 m/s

Acceleration (a) = 2.5 m/s

2

We know v = u + at

∴ 50 = 30 + 2.5 t

⇒ 50 - 30 = 2.5 t

⇒

$\frac{20}{2.5}$

= t or 8 = t

∴ Time taken to accelerate = 8 seconds

Answer 2

Answer:

s = 20.466 m

Explanation:

$s=ut+\frac{1}{2}at^{2}$