Question

if the car starts from rest and moves with an acceleration of 5m/s^2 in 30 sec . calculate the final velocity of the car ​

Answer 1

Given :

• Acceleration of the car = 5 m/s²
• Time Taken (t) = 30 seconds .

To Find :

• Final Velocity of the car .

Solution :

$\longmapsto\tt{Acceleration(a)=5\:{m/s}^{2}}$

$\longmapsto\tt{Initial\:Velocity(u)=0\:m/s}$

$\longmapsto\tt{Time\:Taken(t)=30\:sec}$

Using 1st Equation :

$\longmapsto\tt\boxed{v=u+at}$

Putting Values :

$\longmapsto\tt{v=0+5(30)}$

$\longmapsto\tt{v=0+150}$

$\longmapsto\tt\bf{v=150\:m/s}$

So , The Final Velocity of the car is 150 m/s .

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Three Equations Of Motion :

• v = u + at
• s = ut + 1/2 at²
• v² - u² = 2as

Here :

• v = Final Velocity
• u = Initial Velocity
• t = Time Taken
• a = Acceleration
• s = Distance Travelled

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Answer 2

$\frak{\huge{AnswEr :}}$

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Given Parameters :

• Initial velocity of the car is 0 m/s.

• Acceleration of the car is 5 m/s².

• Time taken by the car is 30 sec.

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Neet to calculate: The final velocity of the car.

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Given that the car starts from rest and moves with an acceleration of 5m/s² in 30 sec.

We have to calculate the final velocity of the car. It can be calculated by using the equation of motion.

You can easily derive the equations of motion by algebraic, calculus & by graphic method.

By using the first equation of motion :

$\bf{\dag} \boxed{\bf{v = u + at}}$

Where,

• v = Final velocity.
• u = Initial velocity.
• a = Acceleration.
• t = Time taken.

Substituting all the given values :

$\\ \sf{:\implies v = 0 + 5 \times 30} \\ \\ \\ \sf{:\implies v = 0 + 150} \\ \\ \\ \sf{:\implies \boxed{ \frak{ \pink{v = 150}}}}$

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$\therefore\textsf{\underline{The final velocity of the car is \textbf{150}\textbf{m/s}}}$