Physics, asked by kanisharawat2, 11 months ago

if the car starts from stationary and travel 6m in 30 sec when the driver apply Brake the Car travel 4 min for only 30 sec find the acceleration of the car​

Answers

Answered by Rohit65k0935Me
11

***** Hey,mate. *****

Given,

Given,Initial Velocity(u)=0m/s

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/s

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secs

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secsAcceleration=?

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secsAcceleration=?v=u +at

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secsAcceleration=?v=u +atv=0+a(30)

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secsAcceleration=?v=u +atv=0+a(30)6=0+a(30)

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secsAcceleration=?v=u +atv=0+a(30)6=0+a(30)6-0=a(30)

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secsAcceleration=?v=u +atv=0+a(30)6=0+a(30)6-0=a(30)6/30=a

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secsAcceleration=?v=u +atv=0+a(30)6=0+a(30)6-0=a(30)6/30=aa=1/5 m/s-2

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secsAcceleration=?v=u +atv=0+a(30)6=0+a(30)6-0=a(30)6/30=aa=1/5 m/s-2a=0.2m/s-2

Given,Initial Velocity(u)=0m/sFinal Velocity(v)=6m/stime(t)=30 secsAcceleration=?v=u +atv=0+a(30)6=0+a(30)6-0=a(30)6/30=aa=1/5 m/s-2a=0.2m/s-2CASE II

Given,

Given,Initial Velocity(u)=6m/s

Given,Initial Velocity(u)=6m/sFinal Velocity(v)=4m/s

Given,Initial Velocity(u)=6m/sFinal Velocity(v)=4m/stime(t)=5 secs

Given,Initial Velocity(u)=6m/sFinal Velocity(v)=4m/stime(t)=5 secsacceleration=?

Given,Initial Velocity(u)=6m/sFinal Velocity(v)=4m/stime(t)=5 secsacceleration=?v=u+at

Given,Initial Velocity(u)=6m/sFinal Velocity(v)=4m/stime(t)=5 secsacceleration=?v=u+at4=6+a(5)

Given,Initial Velocity(u)=6m/sFinal Velocity(v)=4m/stime(t)=5 secsacceleration=?v=u+at4=6+a(5)4-6=a(5)

Given,Initial Velocity(u)=6m/sFinal Velocity(v)=4m/stime(t)=5 secsacceleration=?v=u+at4=6+a(5)4-6=a(5)-2/5=a

Given,Initial Velocity(u)=6m/sFinal Velocity(v)=4m/stime(t)=5 secsacceleration=?v=u+at4=6+a(5)4-6=a(5)-2/5=aa=-0.4m/s-2.

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kanisharawat2: Ooh God this is righ
kanisharawat2: right
kanisharawat2: ???
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