If the center of a triangle with vertices (a, 3), (4, b) and (-3,2) is (1,4) then a =
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Answer:
(1,4) is the centroid of the triangle having the vertices (a,3)(4,b) and (−3,2)
∴(1,4)=(
3
a+4−3
,
3
3+b+2
)
∴(1,4)=(
3
a+1
,
3
b+5
)
∴
3
a+1
=1,
3
b+5
=4
∴a+1=3 b+5=12
∴a=2 b=7.
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