If the centre and radius of the circle is (3,4) and 7 units respectively,then what is the position of the point AB with respect to the circle ? Please reply as soon as possible . thank you
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centre = (3,4)
Radius = 7
The equation of the circle will be:
x^2 + y^2 -6x -8y+24= 0
The position of point AB is determined by replacing x,y by the coordinates of poiny AB in the equation .
x'^2 + y'^2 -6x' -8y' +24
If the value of the equation is
1. less than zero then the point lie inside the circle.
2 equal to zero then the point lie on the circle.
3. greater than zero then the point lie outside the circle.
hope this helped you,
plzzz mark as brainliest .............................!
Radius = 7
The equation of the circle will be:
x^2 + y^2 -6x -8y+24= 0
The position of point AB is determined by replacing x,y by the coordinates of poiny AB in the equation .
x'^2 + y'^2 -6x' -8y' +24
If the value of the equation is
1. less than zero then the point lie inside the circle.
2 equal to zero then the point lie on the circle.
3. greater than zero then the point lie outside the circle.
hope this helped you,
plzzz mark as brainliest .............................!
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