If the centre of a circle is ( − 2 , − 6 ) and the end points of its diameter are ( 1 , − 7 ) and ( x , − 5 ) , find the value of x .
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Let the coordinates of the one end of a diameter AB of a circle are A(2,3) and B(x,y).
Let the coordinates of the center of the circle C(−2,5).
As center is the midpoint of the diameter AB so the coordinates of center is
C(22+x,23+y)
Now equating the coordinates of center we get
22+x=−2
⇒2+x=−4
⇒x=−4−2
⇒x=−6
23+y=5
⇒3+y=10
⇒y=10−3
⇒y=7
∴Coordinates of B=(−6,7).
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