Question

if the centre of a circle is 3, 5 and end point of a diameter are 4, 7 and 2,y then the value of Y is​

Answer 1

Answer:

Hey there

(x1 - x)(x2 - x) + (y1 - y)(y2 - y) = 0

(4 - 3)(2 - 3) + (7 - 5)(y - 5) = 0

- 1 + 2y - 10 = 0

2y = 11

y = 11/2

hope it helps you

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Answer 2

The value of y is 3

Step-by-step explanation:

Given : (3,5) is the center of a circle and the points of diameter is P(4,7) and Q(2,y)

Now Let $(x,y)=(3,5) \text { , } (x_1,y_1) = (4,7) \text { and } (x_2,y_2)= (2,y)$

Now center is the mid point of diameter

therefore by mid point formula

$(x,y)=(\dfrac{x_1+x_2}{2} ,\dfrac{y_1+y_2}{2} )\\\\\Rightarrow \\(3,5)=(\dfrac{4+2}{2}, \dfrac{7+y}{2})$

Comparing the values of y we get

$5=\dfrac{7+y}{2}$

10 = 7+y

y= 10-7

y=3

Hence the value of y is 3

#Learn more

Coordinates of midpoint of triangle is (1,2) (0,-1) and (2,-1). Find the coordinates of vertices

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