If the centre of a circle is (3, 5) and end points of a diameter are (4,7) and
(2, y), then the value of y is
(a) 3
(b) -3
(c) 7
(d) 4
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hey,see the attachment
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Given : (3,5) is the center of a circle and the points of diameter is P(4,7) and Q(2,y)
Now Let (x,y)=(3,5) \text { , } (x_1,y_1) = (4,7) \text { and } (x_2,y_2)= (2,y)(x,y)=(3,5) , (x
1
,y
1
)=(4,7) and (x
2
,y
2
)=(2,y)
Now center is the mid point of diameter
therefore by mid point formula
Step-by-step explanation:
#mayank'sAnsweR
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