If the centroid of a triangle formed by the points (a,b),(b,c),(c,a) is At origin then a³+b³+c³=???
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If the vertices of the ∆ABC be A(a,b) ; B(b,c) ; C(c,a)
Then the coordinates of the centroid will be
P(x,y)= {(a+b+c)/3, (a+b+c)/3};P(x,y)=(0,0)…….. (given)
=> (a+b+c)=0
Using identity
a^3+b^3+c^3–3abc= (a+b+c)(a^2+b^2+c^2-ab-bc-ca)a^3+b^3+c^3–3abc=0a^3+b^3+c^3=3abc
Then the coordinates of the centroid will be
P(x,y)= {(a+b+c)/3, (a+b+c)/3};P(x,y)=(0,0)…….. (given)
=> (a+b+c)=0
Using identity
a^3+b^3+c^3–3abc= (a+b+c)(a^2+b^2+c^2-ab-bc-ca)a^3+b^3+c^3–3abc=0a^3+b^3+c^3=3abc
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