if the centroid of a triangle given points (1,1) , (2,2) and (x,y) is at origin
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Answer:
Let (x
1
,y
1
)≡(1,1);(x
2
,y
2
)≡(0,−7);(x
3
,y
3
)≡(−4,0)
Centroid =(
3
x
1
+x
2
+x
3
,
3
y
1
+y
2
+y
3
)
=(
3
1+0−4
,
3
1−7+0
)
=(
3
−3
,
3
−6
)
Centroid =(−1,−2)
The distance between centroid (−1,−2) and origin (0,0) is
(−1−0)
2
+(−2−0)
2
=
1+2
=
3
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