Question

If the centroid of a triangle is (-2,1) and vertices and (3,-5) (x,y) (10,-2) then find the third vertex of a triangle​

Answer 1

Answer:

$centroid = ( \frac{3 + x + 10}{3} . \frac{ - 5 + y - 2}{3} ) \\ = ( \frac{13 + x}{3} . \frac{ - 7 + y}{3} )$

therefore

$\frac{13 + x}{3} = - 2 \\ 13 + x = - 6 \\ x = - 19$

$\frac{ - 7 + y}{3} = 1 \\ - 7 + y = 3 \\ y = 10$