If the centroid of the triangle two of whose vertices are (2,1) and (1, 2) is (0, 0) , then the third
vertex is
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Centroid Cx = (x₁ + x₂ + x₃)/3
Cy = (y₁ + y₂ + y₃)/3
Cx = 2 Cy = 1 ( given )
=> 2 = (1+0+x₃)/3
=> 6 = 1 + x₃ [ on crore multiplication ]
=> 6 - 1 = x₃
=> x₃ = 5
1 = (2+0+y₃)/3
=> 3 = 2 + y₃
=> 3 - 2 = y₃
=> y₃ = 1
therefore coordinates of the third vertex is (5, 1)
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