if the centroid of triangle is at (10,7) and two vertices are (3,2) and (5,-11) find the third vertex of a triangle
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Given : (10 , 7 ) is the centroid of the triangle with (3 , 2) and (5 , -11) as the two vertices
To find : the third vertex
Solution:
Centroid (x , y ) = ( ( x₁ + x₂ + x₃) /3 , (y₁ + y₂ + y₃) /3 )
Centroid (x , y ) = (10 , 7)
A = (3,2 )
B = (5, -11)
C = (Cx , Cy )
=> 10 = ( 3 + 5 + Cx)/ 3 => Cx = 22
7 = ( 2 -11 + Cy)/3 => Cy = 30
Hence third vertex is ( 22 , 30 )
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