Question

If the change in enthalpy associated with vaporization of benzene at it
boiling point (353 K) is 31.064 kJ mol', then its entropy change of
vaporization will be

Answer 1

Answer:

please refer to the attachments

Answer 2

Given:

Change in Enthalpy in Vaporization of benzene = 31.064 $kJmol^{-1}$

Temperature = 353 $K$

To Find:

Change in Entropy of benzene in Vaporization = ?

Solution:

Entropy is related with the disorderness of system

It is that energy that does not available for doing work

Entropy is ratio between enthalpy with time

Enthalpy and enthalpy is state function.

We can find the value of entropy change in vaporization

Entropy-

$dS = \dfrac{dH}{dT}$

ΔH = 31.064 $kJmol^{-1}$

T    = 353 $K$

ΔS = $\dfrac{31.064}{353}$

ΔS = 88 $J mol^{-1}K^{-1}$