Question

If the change in the momentum of a body in 0.01 sec is 10kgm/s. Then the force acting on
this body will be(a) 10N (b)0.1N (C)100N. (d) 1000N. Solve the problem numerically.
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Answer 1

Given:

Change in Momentum = 10 kgm/s

Time = 0.01 sec

To find:

Force acting on the body

Concept:

Force is defined as the instantaneous rate of change of momentum with respect to time. In other words , we can say that force is equal to the ratio of "momentum change" and time

Calculation:

$\therefore \: force = \dfrac{\Delta(momentum) }{\Delta(time) }$

$= > force = \dfrac{10}{0.01}$

$= > force = \dfrac{10}{ {10}^{ - 2} }$

$= > force = {10}^{3} \: N$

So the final answer is :

Force exerted on object is 1000 N or 1 KN.

Answer 2

Given ,

Change in momentum (ΔP) = 10 kgm/s

Time (t) = 0.01

As we know that ,

• The rate of charge of momentum is called force

• The SI unit of force is " newton " or kg•m/s²

• It is vector quantity

Thus ,

$\sf \mapsto Force = \frac{10}{0.01} \\ \\ \sf \mapsto Force = 10 \times 100 \\ \\ \sf \mapsto Force = 1000 \: newton$

$\therefore \sf \underline{The \: force \: is \: 1000 \: newton }$