Question

If the charge of an electron is 1.6 x 10-19 coulomb, how many electrons should pass through a conductor in 1 second to constitute 1 ampere of current

Answer 1

Given that

Charge (Q) = 1 C

Electron (e) = 1.6× 10^-19

Number of electron (n) = ?

Q= ne

1 C = n × 1.6×10^-19 C

n = 1/(1.6×10^-19)

n = 6.25 × 10^18 electron

Answer 2

Answer:

6.25x10^18

Explanation:

Charge (Q) = 1 C  (Given)

Electron (e) = 1.6× 10^-19  (Given)

Number of electron (n) = We need to find

Now, 1C/s= 1 ampere.

Suppose n electrons make 1C. Then,

=  ne /s= 1 ampere

Solving by unitary method, where - Q = ne

Therefore, n=1(ampere)/(1.6x10^-19)C

= 0.625x10^19/s

= 6.25x10^18

Thus, 6.25x10^18 electrons per second should pass through a conductor in 1 second to constitute 1 ampere of current.