Question

If the charge on an electron is 1.602 x 10-19 C, Find the approximate

number of electrons in1C.​

Answer 1

charge on 1 e‐ = 1.602× 10^-¹⁹

total charge (Q)=1C

n=?

we know that

Q=n×e-

putting given values

1= n × 1.602×10^-¹⁹

n = 1/1.602× 10^‐¹⁹

n = 10¹⁹/1.602

n = 10000×10¹⁸/1602

n= 6.242×10¹⁸ e-

Answer 2

Answer:

$n = \frac{1c}{1.602 \times {10}^{ - 19}c }$

Explanation:

Here, 1 electron is one part of 1c

And, an electron holds

$1.602 \times {10}^{ - 19}c$

of charge.

So, to find the count of parts in 1c

we divide(/) it by

charge in one part.