Question

If the charge on electron is 1.6×10 ki power -19C. How many electron should pass through a conductor in 1 second to constitute1 Ampere​

Answer 1

Answer

6.25 X 10^18

Solution

Given

charge on electron = 1.6 X 10^-19

AS WE KNOW THAT,

I = Q / T

1A = Q / 1s

Q = 1C

Now when charge is 1.6 X 10^-19 coulomb

then number of electron = 1

when charge is 1C then number of electron =

1 / 1.6 X 10^-19C

0.625 X 10^19

6.25 X 10^18C = ANSWER

Answer 2

$\bigstar$ Answer $\bigstar$

$\checkmark$ Given:

Charge on electron ( e ) = $\rm 1.6 \times 10^{-19} \ C$

Current ( $\rm I$ ) = 1 A

Time ( t ) = 1 second

$\checkmark$ To Find:

How many electron should pass through a conductor in 1 second to constitute 1 Ampere

$\checkmark$ Solution:

We know that,

$\orange{\star \ \ \boxed{\rm Q= \pm ne}}$

Here,

• Q = Charge
• n = Number of Electrons
• e = Charge = $\rm 1.6 \times 10^{-19} \ C$

We also know that,

$\red{ \star \ \ \boxed{\rm Q=It}}$

Here,

• Q = Charge
• $\rm I$ = Current
• t = Time

$\dagger$ Equating both the Q

We get,

$\blue{\implies \rm ne=It}$

According to the Question,

We are asked to find how many electron should pass through a conductor in 1 second to constitute 1 Ampere

Hence,

We should find " n "

Therefore,

$\green{\rm \implies n=\dfrac{It}{e}}$

Given that,

$\longrightarrow \ \rm I=1 \ A$

$\rm \longrightarrow \ t=1 \ s$

$\longrightarrow \ e=1.6 \times 10^{-19} \ C$

Hence,

Substituting the values,

We get,

$\red{\rm \implies n=\dfrac{1 \times 1}{1.6 \times 10^{-19}}}$

$\blue{\rm \implies n=\dfrac{1}{1.6} \ \times 10^{19}}$

$\green{\rm \implies n=0.625 \times 10^{19} \ electrons}$

$\orange{\rm \implies n=6.25 \times 10^{18} \ electrons}$

$\sf Therefore,$

$\boxed{\rm No. \ of \ electrons=6.25 \times 10^{18} \ e^{-}}$