Question

If the chord of the segment of a circle is 66 cm and the height the segment is 10 cm find the radius of the circle

Answer 1

$\bf \: we \: know \: that \\ \\ \sf \: am = bm = \frac{ab}{2} = \frac{66}{2} = 33 \\ \\ \sf \: in \: \triangle oam \\ \\ \sf \: {oa}^{2} = {om}^{2} + {am}^{2} \\ \\ \sf \: \implies {(10)}^{2} + {(33)}^{2} \\ \\ \implies \: 100 + 1089 \\ \\ \implies \: \sf \: {oa}^{2} = 1189 \\ \\ \sf \purple {radius = oa = 34.48 \: cm}$