Math, asked by mohitsingh577, 7 months ago

if the circle are drawn taking two sides of a triangle as diameter. prove that the point of intersection of these circles lie on the third side.
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Answered by dineshsahu8024
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Answered by rajivbansal0842
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If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lies on the third side. ... Hence, the circle described on AC as diameter must pass through D. Thus, the two circles intersect in D. Now, ∠ADB + ∠ADC = 180°.

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