if the circle x2+y2-2x+4y+1=0 complete one revolution on the positive direction of X axis then the centre in new position is
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Given : circle x²+y²-2x+4y+1=0 complete one revolution on the positive direction of X axis
To Find : the center in new position is
Solution:
x²+y²-2x+4y+1=0
=> (x - 1)² - 1 + ( y + 2)² - 4 + 1 = 0
=> (x - 1)² + ( y + 2)² = 2²
Center = ( 1 , - 2)
Radius = 2
After one complete revolution
Center will be shifted by 2πr = 4π as r = 2
Hence center = ( 1 + 4π , - 2)
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